Question

based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? increases?

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $V = IR$, where $V$ is voltage, $I$ is current, and $R$ is resistance. We can rewrite it as $I=\frac{V}{R}$.

Step2: Analyze the relationship

Assume voltage $V$ is constant. When resistance $R$ decreases, the denominator of the fraction $\frac{V}{R}$ gets smaller. Since $V$ is fixed, the value of the fraction $\frac{V}{R}$ (which is current $I$) increases. When resistance $R$ increases, the denominator of the fraction $\frac{V}{R}$ gets larger, and the value of the fraction (current $I$) decreases.

Answer:

As the resistance decreases, the current in a circuit increases. As the resistance increases, the current in a circuit decreases.