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Question
basic probability review worksheet - fall 2025
a 6 - sided die is rolled one time. find:
- p(roll a 5)
- p(roll a 1 or 6)
- p(odd #)
- p(multiple of 3)
- p(not a 4)
a card is drawn from a standard 52 - card deck. find:
- p(ace)
- p(red)
- p(diamond)
- p(face)
- p(2 or 3)
- p(black or heart)
- p(not a king)
- p(not a face)
there are 6 red, 3 blue, and 1 white marbles in a jar. find:
- p(blue)
- p(red or white)
- p(green)
- p(non - white)
- p(non - yellow)
a random number from 1 to 20 is drawn from a hat. find:
- p(7)
- p(6 or lower)
- p(18 or higher)
- p(multiple of 4)
- p(9 or 11)
- p(not a 15)
- p(21)
Step1: Recall probability formula
The probability formula is $P(A)=\frac{n(A)}{n(S)}$, where $n(A)$ is the number of favorable outcomes and $n(S)$ is the total number of outcomes.
Step2: Solve for P(7) (Question 19)
There is 1 favorable outcome (the number 7) and 20 total outcomes (numbers from 1 - 20). So $P(7)=\frac{1}{20}$.
Step3: Solve for P(6 or lower) (Question 20)
The favorable outcomes are 1, 2, 3, 4, 5, 6. So $n(A) = 6$ and $n(S)=20$. Then $P(6\text{ or lower})=\frac{6}{20}=\frac{3}{10}$.
Step4: Solve for P(18 or higher) (Question 21)
The favorable outcomes are 18, 19, 20. So $n(A)=3$ and $n(S) = 20$. Then $P(18\text{ or higher})=\frac{3}{20}$.
Step5: Solve for P(multiple of 4) (Question 22)
The multiples of 4 from 1 - 20 are 4, 8, 12, 16, 20. So $n(A)=5$ and $n(S)=20$. Then $P(\text{multiple of }4)=\frac{5}{20}=\frac{1}{4}$.
Step6: Solve for P(9 or 11) (Question 23)
There are 2 favorable outcomes (9 and 11) and 20 total outcomes. So $P(9\text{ or }11)=\frac{2}{20}=\frac{1}{10}$.
Step7: Solve for P(not a 15) (Question 24)
The number of non - 15 outcomes is $20 - 1=19$. So $P(\text{not a }15)=\frac{19}{20}$.
Step8: Solve for P(21) (Question 25)
There are 0 favorable outcomes (21 is not in the range 1 - 20) and 20 total outcomes. So $P(21)=0$.
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- $\frac{1}{20}$
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- $\frac{3}{20}$
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- $\frac{1}{10}$
- $\frac{19}{20}$
- $0$