Question

before: $p_1 + p_2 = -18 \text{ kg m/s}$ assuming momentum is conserved, what is $p_2$? $p_1 = -15 \text{ kg m/s}$ $p_2 = ? \text{ kg m/s}$ -3 kg m/s -18 kg m/s +3 kg m/s -33 kg m/s

Explanation:

Step1: Apply conservation of momentum

$P_1 + P_2 = P'_1 + P'_2$

Step2: Rearrange to solve for $P'_2$

$P'_2 = (P_1 + P_2) - P'_1$

Step3: Substitute given values

$P'_2 = -18 - (-15)$

Step4: Calculate the result

$P'_2 = -18 + 15 = -3$

Answer:

-3 kg m/s