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blood alcohol concentrations of drivers involved in fatal crashes and t…

Question

blood alcohol concentrations of drivers involved in fatal crashes and then given jail sentences are shown below. find the mean, median, and mode of the listed numbers. the mean is (round to the nearest thousandth as needed.) 0.28 0.17 0.17 0.15 0.13 0.25 0.29 0.25 0.14 0.15 0.10 0.15

Explanation:

Step1: Recall mean formula

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. Here, $n = 15$ and the data points are $0.28,0.17,0.17,0.15,0.13,0.25,0.29,0.25,0.14,0.15,0.10,0.15,0.15$.

Step2: Calculate the sum of data - points

$\sum_{i = 1}^{15}x_{i}=0.28 + 0.17+0.17+0.15+0.13+0.25+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=0.28+0.34 + 0.15+0.13+0.25+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=0.62+0.15+0.13+0.25+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=0.77+0.13+0.25+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=0.90+0.25+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=1.15+0.29+0.25+0.14+0.15+0.10+0.15+0.15$
$=1.44+0.25+0.14+0.15+0.10+0.15+0.15$
$=1.69+0.14+0.15+0.10+0.15+0.15$
$=1.83+0.15+0.10+0.15+0.15$
$=1.98+0.10+0.15+0.15$
$=2.08+0.15+0.15$
$=2.23+0.15$
$=2.38$.

Step3: Calculate the mean

$\bar{x}=\frac{\sum_{i = 1}^{15}x_{i}}{15}=\frac{2.38}{15}\approx0.159$.

Answer:

$0.159$