Question

1. build the net ionic equation for the reaction that produces the lead(ii) iodide precipitate. a net ionic equation shows only the ions that participate in the reaction. these are the ions that react to form the precipitate. ions that remain aqueous in a reaction are called spectators. the spectator ions are not included in the net ionic equation. what is a net ionic equation? ? cation + ? anion → ? precipitate please select a valid drop area choices: reset 2 pbi₂ pb²⁺ 1 i₂ pb i

Explanation:

Step1: Identify the ions involved

Lead(II) iodide ($PbI_2$) is formed from lead - two ions ($Pb^{2 + }$) and iodide ions ($I^-$).

Step2: Write the net - ionic equation

The net - ionic equation for the formation of lead(II) iodide precipitate is $Pb^{2+}(aq)+2I^-(aq)
ightarrow PbI_2(s)$.

Answer:

$Pb^{2+}+2I^-
ightarrow PbI_2$