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calculate the ph of a solution if oh⁻ = 1.0 x 10⁻¹². place a check mark…

Question

calculate the ph of a solution if oh⁻ = 1.0 x 10⁻¹². place a check mark on the correct solution type... ph = type acid neutral base

Explanation:

Step1: Calculate pOH

The formula for pOH is $pOH = -\log[OH^-]$. Given $[OH^-]=1.0\times 10^{-12}$, then $pOH=-\log(1.0\times 10^{-12}) = 12$.

Step2: Calculate pH

We know the relationship $pH + pOH=14$. So $pH=14 - pOH$. Substituting the value of pOH, we get $pH = 14- 12=2$.

Step3: Determine solution type

Since $pH = 2<7$, the solution is an acid.

Answer:

pH = 2
ACID