Question

calculate the probability of drawing a: green card, then drawing a blue card, with no replacement. answer as a fraction in lowest terms. enter the numerator.

Explanation:

Step1: Count total and green cards

There are 10 cards in total and 5 green cards.
The probability of drawing a green card first, $P(G_1)=\frac{5}{10}$.

Step2: Calculate probability of blue card after green

After drawing a green card without replacement, there are 9 cards left and 3 blue cards.
The probability of drawing a blue card second given a green card was drawn first, $P(B_2|G_1)=\frac{3}{9}$.

Step3: Use multiplication rule for dependent events

The probability of both events happening is $P(G_1\cap B_2)=P(G_1)\times P(B_2|G_1)=\frac{5}{10}\times\frac{3}{9}=\frac{15}{90}=\frac{1}{6}$. The numerator of the fraction in lowest - terms is 1.

Answer:

1