Question

calculate what will be the volume of 17.0 grams of ammonia (nh₃) at stp?

Explanation:

Step1: Recall Ideal Gas Law

The ideal gas law is \( PV = nRT \), where \( P \) is pressure, \( V \) is volume, \( n \) is moles, \( R \) is gas constant, \( T \) is temperature. At STP (Standard Temperature and Pressure: \( T = 273.15\ K \), \( P = 1\ atm \)), 1 mole of any gas occupies \( 22.4\ L \) (molar volume at STP).

Step2: Calculate moles of \( NH_3 \)

Molar mass of \( NH_3 \): \( N = 14\ g/mol \), \( H = 1\ g/mol \), so \( M = 14 + 3(1) = 17\ g/mol \).
Moles \( n = \frac{mass}{molar\ mass} = \frac{10.0\ g}{17\ g/mol} \approx 0.588\ mol \).

Step3: Find volume at STP

Using molar volume: \( V = n \times 22.4\ L/mol \).
\( V = 0.588\ mol \times 22.4\ L/mol \approx 13.1\ L \) (matches option C).

Answer:

C. 13.1 L