Question

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a candy is randomly drawn from a box with 6 chocolates, 13 candy canes, and 11 lollipops. event a: lollipop event b: candy cane p(a or b) =? hint: p(a or b) = p(a) + p(b) round your answer to the nearest hundredth.

Explanation:

Step1: Calculate total number of candies

$6 + 13+11=30$

Step2: Calculate $P(A)$

$P(A)=\frac{11}{30}$

Step3: Calculate $P(B)$

$P(B)=\frac{13}{30}$

Step4: Calculate $P(A\ or\ B)$

$P(A\ or\ B)=P(A)+P(B)=\frac{11}{30}+\frac{13}{30}=\frac{11 + 13}{30}=\frac{24}{30}=0.80$

Answer:

$0.80$