Question

carry out each calculation and give the answer using the proper number of significant figures.
part 1 of 2
130.99 ml + 0.131 ml + 66.0 ml = 197.1 ml
part 2 of 2
87.0 s - 33. s = s

Explanation:

Part 1:

Step 1: Add the first two volumes

We first add \(130.99\space mL\) and \(0.131\space mL\).
\(130.99 + 0.131=131.121\space mL\)

Step 2: Add the result to the third volume

Now we add \(131.121\space mL\) and \(66.0\space mL\).
\(131.121+ 66.0 = 197.121\space mL\)

Step 3: Determine significant figures

When adding, the number of decimal places in the result should match the least number of decimal places in the terms. \(130.99\) has two decimal places, \(0.131\) has three, and \(66.0\) has one. So we round to one decimal place.
\(197.121\approx197.1\space mL\) (since the digit after the first decimal place is 2, which is less than 5, we don't round up)

Step 1: Subtract the two values

We need to calculate \(87.0\space s- 33.\space s\) (assuming \(33.\space s\) has one significant figure after the decimal? Wait, actually \(87.0\) has three significant figures and \(33.\) (if it's \(33.0\) or \(33\) ? Wait, the problem shows \(87.0\space s - 33.\space s\), maybe it's a typo and should be \(33.0\space s\) or \(33\space s\). But if we take \(87.0 - 33 = 54.0\) (if we consider significant figures, \(87.0\) has three, \(33\) has two, so the result should have two decimal places? Wait, no, for subtraction, the number of decimal places matters. \(87.0\) has one decimal place, \(33.\) (if it's \(33\) with no decimal) has zero. So we go by the least number of decimal places, which is zero? But that seems odd. Wait, maybe it's \(33.0\space s\). Let's assume it's \(33.0\space s\) (maybe a typo in the problem). Then:

Step 1: Subtract the two values

\(87.0- 33.0 = 54.0\space s\)

If we take \(33\space s\) (no decimal), then \(87.0 - 33=54.0\) (since \(87.0\) has one decimal place, we can write it as \(54.0\) to show the precision from \(87.0\)).

Answer:

\(197.1\space mL\)

Part 2: