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in a certain online computer game, there are 48 players who are not on …

Question

in a certain online computer game, there are 48 players who are not on the green team and 100 players total in the game. the game randomly chooses a player to receive a bonus. let the event a and the event b be as follows. a: the player the game chooses is not on the green team. b: the player the game chooses is on the green team. find the following probabilities. write your answers as decimal numbers and do not round. p(a)= p(b)=

Explanation:

Step1: Recall probability formula

The probability of an event $E$ is given by $P(E)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$.

Step2: Calculate $P(A)$

The number of players not on the Green - Team is 48 and the total number of players is 100. So, $P(A)=\frac{48}{100}$.

Step3: Calculate $P(B)$

The number of players on the Green - Team is $100 - 48=52$. So, $P(B)=\frac{52}{100}$.

Answer:

$P(A)=0.48$
$P(B)=0.52$