Question

ch 12* in a table of random digits such as table b, each digit is equally likely to be any of 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. what is the probability that a digit in the table is a 7? 1/9 7/10 9/10 1/10

Explanation:

Step1: Identify total and favorable outcomes

Total possible digits are 0 - 9, so $n_{total}=10$. Favorable outcome (digit is 7) has $n_{favorable}=1$.

Step2: Apply probability formula

The probability formula is $P(A)=\frac{n_{favorable}}{n_{total}}$. Substituting values, we get $P = \frac{1}{10}$.

Answer:

D. 1/10