Question

0 ch₂o + 0 h₂ → 0 ch₃oh

Explanation:

Step1: Identify unbalanced equation

$\text{CH}_2\text{O} + \text{H}_2
ightarrow \text{CH}_3\text{OH}$

Step2: Count H atoms on left

Left side H: $2 + 2 = 4$

Step3: Count H atoms on right

Right side H: $3 + 1 = 4$

Step4: Count C & O atoms

C: 1 on left, 1 on right; O:1 on left,1 on right

Step5: Assign balanced coefficients

All elements are balanced with coefficient 1 for each compound.

Answer:

$\boldsymbol{1\ \text{CH}_2\text{O} + 1\ \text{H}_2
ightarrow 1\ \text{CH}_3\text{OH}}$