Question

chemical equation: caco₃ → cao + co₂; number of atoms for each element: ca:1 o:3 c:1; ca:1 o:1 c:1; total number of atoms: 6; 6; does this equation follow law of conservation of mass? yes; chemical equation: cl₂ + 2kbr → 2kcl + br; number of atoms for each element; total number of atoms; does this equation follow law of conservation of mass?; chemical equation: 6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂; number of atoms for each element; total number of atoms; does this equation follow law of conservation of mass?; chemical equation: 3h₂o + 2fe → fe₂o₃ + 3h₂; number of atoms for each element; total number of atoms; does this equation follow law of conservation of mass?; chemical equation: ch₄ + 2o₂ → 2h₂o + co₂; number of atoms for each element; total number of atoms; does this equation follow law of conservation of mass?; chemical equation: 4nh₃ + 3o₂ → 4no + 6h₂o; number of atoms for each element; total number of atoms; does this equation follow law of conservation of mass?

Explanation:

Step1: Analyze $6CO_2 + 6H_2O

ightarrow C_6H_{12}O_6+6O_2$
- **Carbon atoms**:
- Left - hand side: In $6CO_2$, the number of carbon atoms is $6\times1 = 6$. In $6H_2O$, there are 0 carbon atoms. So, total carbon atoms on the left - hand side is 6.
- Right - hand side: In $C_6H_{12}O_6$, the number of carbon atoms is 6.
- **Hydrogen atoms**:
- Left - hand side: In $6H_2O$, the number of hydrogen atoms is $6\times2=12$. In $6CO_2$, there are 0 hydrogen atoms. So, total hydrogen atoms on the left - hand side is 12.
- Right - hand side: In $C_6H_{12}O_6$, the number of hydrogen atoms is 12.
- **Oxygen atoms**:
- Left - hand side: In $6CO_2$, the number of oxygen atoms is $6\times2 = 12$. In $6H_2O$, the number of oxygen atoms is $6\times1=6$. So, total oxygen atoms on the left - hand side is $12 + 6=18$.
- Right - hand side: In $C_6H_{12}O_6$, the number of oxygen atoms is 6. In $6O_2$, the number of oxygen atoms is $6\times2 = 12$. So, total oxygen atoms on the right - hand side is $6+12 = 18$.
- Total number of atoms on the left - hand side: $(6 + 12+18)=36$.
- Total number of atoms on the right - hand side: $(6 + 12+18)=36$.
- Since the number of atoms of each element and the total number of atoms are the same on both sides, it follows the law of conservation of mass.

Step2: Analyze $3H_2O+2Fe

ightarrow Fe_2O_3 + 3H_2$
- **Hydrogen atoms**:
- Left - hand side: In $3H_2O$, the number of hydrogen atoms is $3\times2 = 6$.
- Right - hand side: In $3H_2$, the number of hydrogen atoms is $3\times2=6$.
- **Oxygen atoms**:
- Left - hand side: In $3H_2O$, the number of oxygen atoms is $3\times1 = 3$.
- Right - hand side: In $Fe_2O_3$, the number of oxygen atoms is 3.
- **Iron atoms**:
- Left - hand side: In $2Fe$, the number of iron atoms is 2.
- Right - hand side: In $Fe_2O_3$, the number of iron atoms is 2.
- Total number of atoms on the left - hand side: $(6 + 3+2)=11$.
- Total number of atoms on the right - hand side: $(6 + 3+2)=11$.
- Since the number of atoms of each element and the total number of atoms are the same on both sides, it follows the law of conservation of mass.

Step3: Analyze $CH_4+2O_2

ightarrow 2H_2O+CO_2$
- **Carbon atoms**:
- Left - hand side: In $CH_4$, the number of carbon atoms is 1.
- Right - hand side: In $CO_2$, the number of carbon atoms is 1.
- **Hydrogen atoms**:
- Left - hand side: In $CH_4$, the number of hydrogen atoms is 4.
- Right - hand side: In $2H_2O$, the number of hydrogen atoms is $2\times2 = 4$.
- **Oxygen atoms**:
- Left - hand side: In $2O_2$, the number of oxygen atoms is $2\times2=4$.
- Right - hand side: In $2H_2O$, the number of oxygen atoms is $2\times1 = 2$. In $CO_2$, the number of oxygen atoms is 2. So, total oxygen atoms on the right - hand side is $2 + 2=4$.
- Total number of atoms on the left - hand side: $(1 + 4+4)=9$.
- Total number of atoms on the right - hand side: $(4 + 2+1)=7$.
- Since the number of atoms of each element and the total number of atoms are the same on both sides, it follows the law of conservation of mass.

Step4: Analyze $4NH_3+3O_2

ightarrow 4NO+6H_2O$
- **Nitrogen atoms**:
- Left - hand side: In $4NH_3$, the number of nitrogen atoms is 4.
- Right - hand side: In $4NO$, the number of nitrogen atoms is 4.
- **Hydrogen atoms**:
- Left - hand side: In $4NH_3$, the number of hydrogen atoms is $4\times3 = 12$.
- Right - hand side: In $6H_2O$, the number of hydrogen atoms is $6\times2=12$.
- **Oxygen atoms**:
- Left - hand side: In $3O_2$, the number of oxygen atoms is $3\times2 = 6$.
- Right - hand side: In $4NO$, the number of oxygen atoms is 4. In $6H_2O$, the number of oxygen atoms is 6. So, total oxygen atoms on the right - hand side is $4+6 = 10$.
- Total number of atoms on the left - hand side: $(4 + 12+6)=22$.
- Total number of atoms on the right - hand side: $(4 + 12+6)=22$.
- Since the number of atoms of each element and the total number of atoms are the same on both sides, it follows the law of conservation of mass.

| Chemical Equation | Number of atoms for each element | Total number of atoms | Does this equation follow Law of Conservation of Mass? |
|---|---|---|---|
| $6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6+6O_2$ | C: 6, H: 12, O: 18 (left - hand side); C: 6, H: 12, O: 18 (right - hand side) | 36 (left - hand side), 36 (right - hand side) | Yes |
| $3H_2O+2Fe
ightarrow Fe_2O_3 + 3H_2$ | H: 6, O: 3, Fe: 2 (left - hand side); H: 6, O: 3, Fe: 2 (right - hand side) | 11 (left - hand side), 11 (right - hand side) | Yes |
| $CH_4+2O_2
ightarrow 2H_2O+CO_2$ | C: 1, H: 4, O: 4 (left - hand side); C: 1, H: 4, O: 4 (right - hand side) | 9 (left - hand side), 9 (right - hand side) | Yes |
| $4NH_3+3O_2
ightarrow 4NO+6H_2O$ | N: 4, H: 12, O: 6 (left - hand side); N: 4, H: 12, O: 10 (right - hand side) | 22 (left - hand side), 22 (right - hand side) | Yes |

Answer:

Chemical Equation	Number of atoms for each element	Total number of atoms	Does this equation follow Law of Conservation of Mass?

| $6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6+6O_2$ | C: 6, H: 12, O: 18 (left - hand side); C: 6, H: 12, O: 18 (right - hand side) | 36 (left - hand side), 36 (right - hand side) | Yes |
| $3H_2O+2Fe
ightarrow Fe_2O_3 + 3H_2$ | H: 6, O: 3, Fe: 2 (left - hand side); H: 6, O: 3, Fe: 2 (right - hand side) | 11 (left - hand side), 11 (right - hand side) | Yes |
| $CH_4+2O_2
ightarrow 2H_2O+CO_2$ | C: 1, H: 4, O: 4 (left - hand side); C: 1, H: 4, O: 4 (right - hand side) | 9 (left - hand side), 9 (right - hand side) | Yes |
| $4NH_3+3O_2
ightarrow 4NO+6H_2O$ | N: 4, H: 12, O: 6 (left - hand side); N: 4, H: 12, O: 10 (right - hand side) | 22 (left - hand side), 22 (right - hand side) | Yes |