Question

a chemist determined by measurements that 0.0550 moles of silver participated in a chemical reaction. calculate the mass of silver that participated in the chemical reaction. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall molar - mass of silver

The molar mass of silver (Ag) is $107.87\ g/mol$.

Step2: Use the mass - mole formula

The formula to calculate mass ($m$) from moles ($n$) and molar mass ($M$) is $m = n\times M$. Here, $n = 0.0550\ mol$ and $M=107.87\ g/mol$. So, $m=0.0550\ mol\times107.87\ g/mol$.

Step3: Perform the calculation

$m = 0.0550\times107.87=5.93285\ g$.

Step4: Consider significant digits

The number of moles ($0.0550$) has three significant digits. So, the mass should be rounded to three significant digits. Rounding $5.93285$ to three significant digits gives $5.93\ g$.

Answer:

$5.93\ g$