Question

chemistry 20 stoichiometry quiz
name: ebtesam
multiple choice

1. how many grams are there in 1.23 mol of barium iodide?

3.14×10⁻³
73.5
481
318

Explanation:

Step1: Find molar mass of $BaI_2$

The molar mass of $Ba$ is approximately $137.33\ g/mol$ and of $I$ is approximately $126.90\ g/mol$. For $BaI_2$, molar mass $M = 137.33+2\times126.90= 137.33 + 253.8=391.13\ g/mol$.

Step2: Calculate mass

We know that $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass and $M$ is the molar mass. Rearranging for $m$, we get $m = n\times M$. Given $n = 1.23\ mol$ and $M=391.13\ g/mol$, then $m=1.23\times391.13 = 480.08\approx481\ g$.

Answer:

481 (corresponding to the third option in the multiple - choice list)