Question

chemistry
identifying compound names and formulas
name:
period:
write the name for each of the following compounds. identify each as ionic (i) or covalent (c).
c 1. n₂s₃
i 2. nh₄cl
______ 3. cuf
______ 4. cuf₂
______ 5. na₂s
______ 6. hg(no₃)₂
______ 7. al₂o₃
______ 8. so₃
______ 9. co₂
______ 10. pbso₄

Explanation:

Problem 2: $\boldsymbol{NH_4Cl}$

Step 1: Identify Compound Type

$NH_4Cl$ has $NH_4^+$ (ammonium ion, a polyatomic cation) and $Cl^-$ (chloride ion, an anion). Ionic compounds form between ions, so it's ionic (I).

Step 2: Name the Ionic Compound

For ionic compounds with polyatomic ions: name the cation first, then the anion. The cation is ammonium ($NH_4^+$), the anion is chloride ($Cl^-$). So the name is ammonium chloride.

Step 1: Identify Compound Type

$CuF$ has $Cu^+$ (copper(I) ion, since fluoride is $F^-$ and charge balance: $Cu^+ + F^- = CuF$) and $F^-$. Ionic (I) as it's a metal - nonmetal compound.

Step 2: Name the Ionic Compound

Cation: copper(I) (since $Cu$ has a +1 charge here, determined by $F^-$ having - 1 and charge balance). Anion: fluoride. Name: copper(I) fluoride (or cuprous fluoride).

Step 1: Identify Compound Type

$CuF_2$ has $Cu^{2+}$ (copper(II) ion, since 2 $F^-$ ions with - 1 each: $Cu^{2+}+2F^- = CuF_2$) and $F^-$. Ionic (I), metal - nonmetal.

Step 2: Name the Ionic Compound

Cation: copper(II) (charge +2). Anion: fluoride. Name: copper(II) fluoride (or cupric fluoride).

Answer:

I, Ammonium Chloride

Problem 3: $\boldsymbol{CuF}$