Question

(d) __ c₄h₆o₃+ h₂o→__ c₂h₄o₂
(e) __ c₂h₄+ o₂→ co₂+__ h₂o
(f) __ c₄h₁₀o+ o₂→ co₂+__ h₂o
(g) __ c₇h₁₆+ o₂→ co₂+__ h₂o
(h) __ h₂sicl₂+ h₂o→ h₈si₄o₄+__ hcl

Explanation:

Step1: Balance (d)

Balance carbon, hydrogen and oxygen atoms.
$C_{4}H_{6}O_{3}+H_{2}O
ightarrow2C_{2}H_{4}O_{2}$

Step2: Balance (e)

For $C_{2}H_{4}+O_{2}
ightarrow CO_{2}+H_{2}O$, balance carbon first, then hydrogen and oxygen.
$C_{2}H_{4}+3O_{2}
ightarrow2CO_{2}+2H_{2}O$

Step3: Balance (f)

For $C_{4}H_{10}O+O_{2}
ightarrow CO_{2}+H_{2}O$, balance carbon, hydrogen and then oxygen.
$C_{4}H_{10}O + 6O_{2}
ightarrow4CO_{2}+5H_{2}O$

Step4: Balance (g)

For $C_{7}H_{16}+O_{2}
ightarrow CO_{2}+H_{2}O$, balance carbon, hydrogen and then oxygen.
$C_{7}H_{16}+11O_{2}
ightarrow7CO_{2}+8H_{2}O$

Step5: Balance (h)

For $H_{2}SiCl_{2}+H_{2}O
ightarrow H_{8}Si_{4}O_{4}+HCl$, balance silicon first, then hydrogen, oxygen and chlorine.
$4H_{2}SiCl_{2}+4H_{2}O
ightarrow H_{8}Si_{4}O_{4}+8HCl$

Answer:

(d) 1, 1, 2
(e) 1, 3, 2, 2
(f) 1, 6, 4, 5
(g) 1, 11, 7, 8
(h) 4, 4, 1, 8