Question

collision forces quick check
a blue car weighing 1,302 kg is accelerating forward at a rate of 4 \\(\frac{m}{s^2}\\). what is the forward force of
the car? (1 point)
\\(\circ\\) 1,298 n
\\(\circ\\) 325.5 n
\\(\circ\\) 1,306 n
\\(\circ\\) 5,208 n

Explanation:

Step1: Recall Newton's Second Law

Newton's second law states that force \( F \) is equal to mass \( m \) multiplied by acceleration \( a \), so the formula is \( F = m \times a \).

Step2: Identify given values

The mass \( m \) of the car is \( 1302 \, \text{kg} \) and the acceleration \( a \) is \( 4 \, \frac{\text{m}}{\text{s}^2} \).

Step3: Calculate the force

Substitute the values into the formula: \( F = 1302 \, \text{kg} \times 4 \, \frac{\text{m}}{\text{s}^2} \).
Calculating the product: \( 1302 \times 4 = 5208 \). So the force \( F = 5208 \, \text{N} \).

Answer:

5,208 N