Question

compare the total mass of the reactants to the total mass of the products. what choice demonstrates the law of conservation of mass? 22gal+175gbr₂→197galbr₃ 50gna+126gcl→140gnacl 178gh₂o→20gh₂+40go₂ 8gh₂+92gcl₂→68ghcl

Explanation:

Step1: Calculate reactant mass (Option1)

$22\ \text{g} + 175\ \text{g} = 197\ \text{g}$

Step2: Compare to product mass (Option1)

$197\ \text{g} = 197\ \text{g}$

Step3: Calculate reactant mass (Option2)

$50\ \text{g} + 126\ \text{g} = 176\ \text{g}$

Step4: Compare to product mass (Option2)

$176\ \text{g}
eq 140\ \text{g}$

Step5: Calculate reactant mass (Option3)

$178\ \text{g}$

Step6: Compare to product mass (Option3)

$20\ \text{g} + 40\ \text{g} = 60\ \text{g}
eq 178\ \text{g}$

Step7: Calculate reactant mass (Option4)

$8\ \text{g} + 92\ \text{g} = 100\ \text{g}$

Step8: Compare to product mass (Option4)

$100\ \text{g}
eq 68\ \text{g}$

Answer:

A. $22\ \text{g}\text{Al} + 175\ \text{g}\text{Br}_2
ightarrow 197\ \text{g}\text{AlBr}_3$