Question

complete the following table to confirm correct lewis dot structure format. this is not the report sheet: formula name skeleton # of valence e⁻ e⁻ used in single bonds remaining electrons complete lewis structure ch₄ methane nh₃ nitrogen trihydride (ammonia) h₂s dihydrogen sulfide hocn cyanic acid h - o - c - n 16e⁻ 10e⁻ 6e⁻ h - ö - c ≡ n: bf₃ boron trifluoride

Explanation:

Step1: Determine valence electrons for CH₄

Carbon has 4 valence electrons and each hydrogen has 1. So total valence electrons = 4+(1×4)=8. Skeleton is C in the center with 4 H's around it. Number of single - bonds is 4, using 8 electrons (2 per bond), and remaining electrons is 0. Complete Lewis structure: H - C(4 H's around it with single bonds).

Step2: Determine valence electrons for NH₃

Nitrogen has 5 valence electrons and each hydrogen has 1. So total valence electrons = 5+(1×3)=8. Skeleton is N in the center with 3 H's around it. Number of single - bonds is 3, using 6 electrons (2 per bond), and remaining electrons is 2 (a lone pair on N). Complete Lewis structure: H - N(-H)(-H) with a lone pair on N.

Step3: Determine valence electrons for H₂S

Sulfur has 6 valence electrons and each hydrogen has 1. So total valence electrons = 6+(1×2)=8. Skeleton is S in the center with 2 H's around it. Number of single - bonds is 2, using 4 electrons (2 per bond), and remaining electrons is 4 (2 lone pairs on S). Complete Lewis structure: H - S(-H) with 2 lone pairs on S.

Step4: Determine valence electrons for BF₃

Boron has 3 valence electrons and each fluorine has 7. So total valence electrons = 3+(7×3)=24. Skeleton is B in the center with 3 F's around it. Number of single - bonds is 3, using 6 electrons (2 per bond), and remaining electrons is 18 (6 lone pairs, 3 on each F). Complete Lewis structure: F - B(-F)(-F) with 3 lone pairs on each F.

Formula	Name	Skeleton	# of valence e⁻	e⁻ used in single bonds	Remaining electrons	Complete Lewis structure
NH₃	nitrogen trihydride (ammonia)	N surrounded by 3 H's	8	6	2	H - N(-H)(-H) with a lone pair on N
H₂S	dihydrogen sulfide	S surrounded by 2 H's	8	4	4	H - S(-H) with 2 lone pairs on S
HOCN	cyanic acid	H - O - C - N	16	10	6	H - O(-C≡N) with 2 lone pairs on O
BF₃	boron trifluoride	B surrounded by 3 F's	24	6	18	F - B(-F)(-F) with 3 lone pairs on each F

Answer:

Formula	Name	Skeleton	# of valence e⁻	e⁻ used in single bonds	Remaining electrons	Complete Lewis structure
NH₃	nitrogen trihydride (ammonia)	N surrounded by 3 H's	8	6	2	H - N(-H)(-H) with a lone pair on N
H₂S	dihydrogen sulfide	S surrounded by 2 H's	8	4	4	H - S(-H) with 2 lone pairs on S
HOCN	cyanic acid	H - O - C - N	16	10	6	H - O(-C≡N) with 2 lone pairs on O
BF₃	boron trifluoride	B surrounded by 3 F's	24	6	18	F - B(-F)(-F) with 3 lone pairs on each F