Question

complete this table.

name	empirical formula
rubidium oxide

Explanation:

Step1: Determine charge of ions for chromium (II) fluoride

Chromium (II) has a charge of $Cr^{2 + }$ and fluoride ion is $F^{-}$. To balance the charges, we need 2 fluoride ions for 1 chromium (II) ion.

Step2: Write empirical formula for chromium (II) fluoride

The empirical formula is $CrF_{2}$.

Step3: Determine charge of ions for rubidium oxide

Rubidium ion is $Rb^{+}$ and oxide ion is $O^{2 - }$. To balance the charges, we need 2 rubidium ions for 1 oxide ion.

Step4: Write empirical formula for rubidium oxide

The empirical formula is $Rb_{2}O$.

Answer:

name	empirical formula
rubidium oxide	$Rb_{2}O$