Question

consider the chemical equations shown here. c(s) + 2h₂(g) → ch₄(g) c(s) + 2cl₂(g) → ccl₄(g) h₂(g) + cl₂(g) → 2hcl(g) what is the overall equation for the reaction that produces ccl₄ and hcl from ch₄ and cl₂? ch₄(g) + cl₂(g) + h₂(g) → ccl₄(g) + hcl(g) ch₄(g) + cl₂(g) → ccl₄+hcl(g)

Explanation:

Step1: Reverse the first equation

$CH_4(g)
ightarrow C(s)+2H_2(g)$

Step2: Keep the second equation as is

$C(s)+2Cl_2(g)
ightarrow CCl_4(g)$

Step3: Multiply the third equation by 2

$2H_2(g)+2Cl_2(g)
ightarrow 4HCl(g)$

Step4: Add the three - modified equations

$CH_4(g)+C(s)+2Cl_2(g)+2H_2(g)
ightarrow C(s)+2H_2(g)+CCl_4(g)+4HCl(g)$
Cancel out the common terms ($C(s)$ and $2H_2(g)$) on both sides.

Answer:

$CH_4(g)+4Cl_2(g)
ightarrow CCl_4(g)+4HCl(g)$