Question

consider the equations. (1) fe₂o₃(s) → 2fe(s) + ³/₂o₂(g) (2) fe₂o₃(s) + 3co(g) → 2fe(s) + 3co₂(g) which equation must be added to equation (1) to produce equation (2)? 3co(g) + ³/₂o₂(g) → 3co₂(g) co(g) + ¹/₂o₂(g) → co₂(g)

Explanation:

Step1: Let the equation to be added be \(x\).

Let equation (1) be \(a = b\) and equation (2) be \(c = d\). So \(a+x=c\). Then \(x = c - a\).

Step2: Subtract equation (1) from equation (2).

\((Fe_2O_3(s)+3CO(g)
ightarrow2Fe(s)+3CO_2(g))-(Fe_2O_3(s)
ightarrow2Fe(s)+\frac{3}{2}O_2(g))\)
\[

$$\begin{align*} Fe_2O_3(s)+3CO(g)-Fe_2O_3(s)&=2Fe(s)+3CO_2(g)-(2Fe(s)+\frac{3}{2}O_2(g))\\ 3CO(g)&=3CO_2(g)-\frac{3}{2}O_2(g)\\ 3CO(g)+\frac{3}{2}O_2(g)&=3CO_2(g) \end{align*}$$

\]

Answer:

\(3CO(g)+\frac{3}{2}O_2(g)
ightarrow3CO_2(g)\)