Question

consider the redox reaction below.
ag⁺(aq) + zn(s) → zn²⁺(aq) + ag(s)
balance the silver half - reaction. how many electrons are transferred?

Explanation:

Step1: Identify the silver half-reaction

The silver species in the reaction is \( \text{Ag}^+(aq) \) on the reactant side and \( \text{Ag}(s) \) on the product side. So the half - reaction for silver is \( \text{Ag}^+(aq)\to\text{Ag}(s) \).

Step2: Balance atoms

The number of silver atoms is already balanced (1 Ag on each side).

Step3: Balance charge

The charge on the left - hand side (LHS) is \( + 1\) (from \( \text{Ag}^+ \)) and on the right - hand side (RHS) is \( 0\) (from \( \text{Ag}(s) \)). To balance the charge, we need to add 1 electron to the left - hand side because electrons have a negative charge. The balanced half - reaction is \( \text{Ag}^+(aq)+e^-\to\text{Ag}(s) \). So the number of electrons transferred in the silver half - reaction is 1.

Answer:

1