Question

copper(ii) chloride
express your answer as a chemical formula.
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part b
copper(i) iodate
express your answer as a chemical formula.
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Explanation:

Part A: copper(II) chloride

Step1: Identify ions

Copper(II) has charge $Cu^{2+}$, chloride is $Cl^-$.

Step2: Balance charges

To balance $2+$ and $1-$, need 2 $Cl^-$. So formula is $CuCl_2$.

Step1: Identify ions

Copper(I) has charge $Cu^+$, iodate is $IO_3^-$.

Step2: Balance charges

$1+$ and $1-$ balance, so formula is $CuIO_3$.

Answer:

$CuCl_2$

Part B: copper(I) iodate