Question

correct answer:the mean price of the phones is $162.progress: 2/3part 3 of 3(c) how does including the price of the inexpensive phone affect the mean?by including the phone for $54, the mean is decreased by $□.

Explanation:

Step1: Define original total and count

Let original number of phones = $n$. Original total price: $162n$

Step2: Calculate new total and mean

New total price: $162n + 54$. New number of phones: $n+1$. New mean: $\frac{162n + 54}{n+1}$

Step3: Find mean decrease amount

Decrease = Original mean - New mean:
$$162 - \frac{162n + 54}{n+1} = \frac{162(n+1) - (162n + 54)}{n+1} = \frac{162n + 162 - 162n - 54}{n+1} = \frac{108}{n+1}$$
However, since this is the final part of a 3-part problem, we infer the original count was 2 phones (progress 2/3, adding 1 makes 3).

Step4: Substitute original count $n=2$

Decrease = $\frac{108}{2+1} = 36$

Answer:

36