QUESTION IMAGE
Question
- create a histogram using the male data.
- using only the histograms, answer the following questions.
2a. how many females eat at least 18 candy bars?
2b. how many males eat exactly 25 candy bars?
2c. how many people eat at least 6 candy bars and less than 20 candy bars?
2d. what is the greatest amount of candy bars eaten among males and females?
2e. what would you consider a typical amount of candy bars eaten by females? explain your reasoning.
discuss with a partner:
- if you used the dot plot to answer the same five questions you just answered, how would your answers be different?
- how are the histogram and the dot plot alike? how are they different?
Since the male data to create the histogram is not provided, we will assume we have the histograms for answering part 2.
Step1: Analyze female - at least 18 candy bars
For 2a, we look at the female - side of the histogram and sum the frequencies of the bars starting from 18 and above.
Step2: Analyze male - exactly 25 candy bars
For 2b, we check the male - side of the histogram and find the frequency of the bar corresponding to 25 candy bars.
Step3: Analyze people - 6 to 20 candy bars
For 2c, we sum the frequencies of the bars on both male and female sides of the histogram that fall in the range of at least 6 and less than 20 candy bars.
Step4: Find greatest amount
For 2d, we look at the highest value on the x - axis (candy bars) that has a non - zero frequency on either the male or female side of the histogram.
Step5: Determine typical amount for females
For 2e, we look at the mode (the most frequent value or the bin with the highest frequency) of the female histogram as a typical amount and explain that the mode represents the most common value in the data set.
However, without the actual histograms, we cannot perform the calculations.
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2a. Cannot be determined without the histogram.
2b. Cannot be determined without the histogram.
2c. Cannot be determined without the histogram.
2d. Cannot be determined without the histogram.
2e. Cannot be determined without the histogram.