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Question
it is critical to understand that when we multiply two polynomials then our result is equivalent to this product and this equivalence can be tested.
exercise #4: consider the product of $(x - 2)$ and $(2x - 5)$.
(a) evaluate this product for $x = 4$. show the work that leads to your result.
(b) find a trinomial that represents the product of these two binomials.
(c) evaluate the trinomial for $x = 4$. is it equivalent to the answer you found in (a)?
(d) what is the value of the trinomial when $x = 2$? can you explain why this makes sense based on the two binomials?
exercise #5: the product of three binomials, just like the product of two, can be found with repeated applications of the distributive property.
(a) find the product: $(x - 2)(x + 4)(x - 7)$. use area arrays to help keep track of the product.
(b) for what three values of $x$ will the cubic polynomial that you found in part (a) have a value of zero? what famous law is this known as?
(c) test one of the three values you found in (b) to verify that it is a zero of the cubic polynomial.
Exercise #4
(a)
Step1: Substitute \( x = 4 \) into the binomials
First, find the value of \( (x - 2) \) when \( x = 4 \): \( 4 - 2 = 2 \)
Then, find the value of \( (2x - 5) \) when \( x = 4 \): \( 2\times4 - 5 = 8 - 5 = 3 \)
Step2: Multiply the two results
Multiply the two values: \( 2\times3 = 6 \)
Step1: Use the distributive property (FOIL method)
Multiply \( (x - 2)(2x - 5) \):
First: \( x\times2x = 2x^2 \)
Outer: \( x\times(-5) = -5x \)
Inner: \( -2\times2x = -4x \)
Last: \( -2\times(-5) = 10 \)
Step2: Combine like terms
Combine the middle terms: \( -5x - 4x = -9x \)
So the trinomial is \( 2x^2 - 9x + 10 \)
Step1: Substitute \( x = 4 \) into the trinomial
Substitute \( x = 4 \) into \( 2x^2 - 9x + 10 \):
\( 2\times4^2 - 9\times4 + 10 = 2\times16 - 36 + 10 \)
Step2: Calculate the value
Calculate each term: \( 32 - 36 + 10 = 6 \)
Compare with the answer in (a) (which is 6), so they are equivalent.
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\( 6 \)