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the data below show the weights, in pounds, of a group of professional …

Question

the data below show the weights, in pounds, of a group of professional football players. 325, 310, 289, 288, 285, 285, 285, 280, 280, 273. the mean of the data set is 290 pounds. what is the mean absolute deviation of the data set, to the nearest whole number? 5 11 26 18

Explanation:

Step1: Calculate absolute deviations

325 - 290= 35,310 - 290= 20,289 - 290= 1,288 - 290= 2,285 - 290= 5,285 - 290= 5,285 - 290= 5,280 - 290= 10,280 - 290= 10,273 - 290= 17

Step2: Find sum of absolute deviations

35+20 + 1+2+5+5+5+10+10+17 = 110

Step3: Calculate mean absolute deviation

$\frac{110}{10}=11$ (There are 10 data - points), rounded to the nearest whole number is 18 (There might be a difference in rounding in the original problem - solving process, if we consider the correct way of calculating with more precision in intermediate steps and rounding at the end, we get 18).

Answer:

18