Question

dave pushes a shopping - cart with a constant force of 10.0 newtons across the floor of a grocery store. the frictional force exerted by the floor is 4.0 newtons, and the acceleration of the cart is 1.0 meters/second². what is the mass of the shopping cart?
10 kilograms
6 kilograms
14 kilograms
4 kilograms

Explanation:

Step1: Determine net - force

The applied force is $F_{applied}=10$ N and the frictional force is $F_{friction}=4$ N. The net - force $F_{net}$ acting on the cart is the difference between the applied force and the frictional force. So, $F_{net}=F_{applied}-F_{friction}$.
$F_{net}=10 - 4=6$ N.

Step2: Use Newton's second law

Newton's second law is $F_{net}=ma$, where $F_{net}$ is the net - force, $m$ is the mass, and $a$ is the acceleration. We know $F_{net}=6$ N and $a = 1$ m/s². We can solve for $m$ by rearranging the formula to $m=\frac{F_{net}}{a}$.
$m=\frac{6}{1}=6$ kg.

Answer:

6 kilograms