Question

decomposition: the breaking down of a chemical compound into its elements or into simpler compounds. example 4: 2hgo → 2hg + o₂ example 5: 2nacl → na + cl₂ example 6: 8h² + 6s⁸ → 6. cl2o5 → 7. n2o5 → + no2 8. alcl3 → 9. fe2s3 → + s8 0. icl →

Explanation:

Step1: Balance the decomposition of $Cl_2O_5$

Decomposition of $Cl_2O_5$ gives $Cl_2$ and $O_2$. We balance the equation using the law of conservation of mass. The balanced equation is $2Cl_2O_5
ightarrow 2Cl_2 + 5O_2$.

Step2: Balance the decomposition of $N_2O_5$

$N_2O_5$ decomposes to $NO_2$ and $O_2$. The balanced equation is $2N_2O_5
ightarrow 4NO_2+O_2$.

Step3: Balance the decomposition of $AlCl_3$

$AlCl_3$ decomposes into its elements $Al$ and $Cl_2$. The balanced equation is $2AlCl_3
ightarrow 2Al + 3Cl_2$.

Step4: Balance the decomposition of $Fe_2S_3$

$Fe_2S_3$ decomposes to $Fe$ and $S_8$. First, we need to balance the sulfur atoms. The balanced equation is $8Fe_2S_3
ightarrow 16Fe+3S_8$.

Step5: Balance the decomposition of $ICl$

$ICl$ decomposes into its elements $I_2$ and $Cl_2$. The balanced equation is $2ICl
ightarrow I_2 + Cl_2$.

Answer:

1. $2Cl_2O_5

ightarrow 2Cl_2 + 5O_2$

1. $2N_2O_5

ightarrow 4NO_2+O_2$

1. $2AlCl_3

ightarrow 2Al + 3Cl_2$

1. $8Fe_2S_3

ightarrow 16Fe+3S_8$

1. $2ICl

ightarrow I_2 + Cl_2$