Question

determine the amount in grams of kcl that exists in 20.3 g of a solution that contains 1.14 % kcl by mass

Explanation:

Step1: Identify starting solution mass

Starting amount: $20.3\ \text{g solution}$

Step2: Apply mass percent conversion

Multiply by $\frac{1.14\ \text{g KCl}}{100\ \text{g solution}}$
Expression: $20.3 \times \frac{1.14}{100}$

Step3: Calculate final mass of KCl

Compute the product: $20.3 \times 0.0114 = 0.23142$

Answer:

$0.231\ \text{g KCl}$

(The filled setup would be:
Starting amount: $20.3$ $\text{g solution}$
Multiplied by $\frac{1.14\ \text{g KCl}}{100\ \text{g solution}}$)