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determine if the finite correction factor should be used. if so, use it…

Question

determine if the finite correction factor should be used. if so, use it in your calculations when you find the probability. in a sample of 700 gas stations, the mean price for regular gasoline at the pump was $2.813 per gallon and the standard deviation was $0.009 per gallon. a random sample of size 50 is drawn from this population. what is the probability that the mean price per gallon is less than $2.809? click here to view information about the finite correction factor. the probability that the mean price per gallon is less than $2.809 is . (round to four decimal places as needed.)

Explanation:

Step1: Check finite - correction factor condition

The finite - correction factor is used when $n/N>0.05$, where $n$ is the sample size and $N$ is the population size. Here, $n = 50$ and $N=700$. Calculate $n/N=\frac{50}{700}\approx0.0714>0.05$, so the finite - correction factor should be used. The formula for the standard deviation of the sample mean with the finite - correction factor is $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\sqrt{\frac{N - n}{N - 1}}$, where $\sigma$ is the population standard deviation, $n$ is the sample size, and $N$ is the population size. Given $\sigma = 0.009$, $n = 50$, and $N = 700$. First, calculate $\sqrt{\frac{N - n}{N - 1}}=\sqrt{\frac{700 - 50}{700 - 1}}=\sqrt{\frac{650}{699}}\approx\sqrt{0.9299}\approx0.9643$, and $\frac{\sigma}{\sqrt{n}}=\frac{0.009}{\sqrt{50}}\approx\frac{0.009}{7.0711}\approx0.0013$. Then $\sigma_{\bar{x}}=0.0013\times0.9643\approx0.00125$.

Step2: Calculate the z - score

The formula for the z - score is $z=\frac{\bar{x}-\mu}{\sigma_{\bar{x}}}$, where $\bar{x}$ is the sample mean, $\mu$ is the population mean. Given $\mu = 2.813$, $\bar{x}=2.809$, and $\sigma_{\bar{x}}\approx0.00125$. Then $z=\frac{2.809 - 2.813}{0.00125}=\frac{- 0.004}{0.00125}=-3.2$.

Step3: Find the probability

We want to find $P(\bar{X}<2.809)$, which is equivalent to $P(Z < - 3.2)$ using the standard normal distribution. Looking up the value in the standard - normal table, $P(Z < - 3.2)=0.0013$.

Answer:

$0.0013$