Question

determine the number of particles in the 8.10 mol sample of c2h4o. 1 mol c2h4o = 6.02×10^23 particles c2h4o 8.10 mol c2h4o = ×10^ particles c2h4o enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

Explanation:

Step1: Set up the proportion

We know that 1 mol of a substance contains $6.02\times 10^{23}$ particles (Avogadro's number). Let $x$ be the number of particles in 8.10 mol of $C_2H_4O$. The proportion is $\frac{1\ mol}{6.02\times 10^{23}\ particles}=\frac{8.10\ mol}{x}$.

Step2: Solve for $x$

Cross - multiply to get $x = 8.10\ mol\times6.02\times 10^{23}\ particles/mol$.
$x=8.10\times6.02\times 10^{23}$ particles.
$8.10\times6.02 = 48.762$.
So $x = 48.762\times 10^{23}$ particles. In scientific notation, this is $4.88\times 10^{24}$ particles (rounded to two decimal places for the coefficient).

Answer:

Coefficient in green box: 4.88
Exponent in yellow box: 24