Question

determine the number of particles in the 2.50 mol sample of nacl. 1 mol nacl = 6.02×10²³ particles nacl 2.50 mol nacl = ×10^ particles nacl enter the coefficient in the green - box and the exponent in the yellow - box. round your coefficient to two decimal places.

Explanation:

Step1: Set up proportion

We know that 1 mol of NaCl has $6.02\times 10^{23}$ particles. Let $x$ be the number of particles in 2.50 mol of NaCl. The proportion is $\frac{1\ mol}{6.02\times 10^{23}\ particles}=\frac{2.50\ mol}{x}$.

Step2: Solve for x

Cross - multiply: $x = 2.50\times6.02\times 10^{23}$.

Step3: Calculate result

$2.50\times6.02 = 15.05$, so $x=15.05\times 10^{23}=1.505\times 10^{24}$ (in scientific notation). Rounding the coefficient to two decimal places, we get $1.51\times 10^{24}$.

Answer:

Coefficient in green box: 1.51
Exponent in yellow box: 24