Question

determine the number of particles in the 3.60 mol sample of al2o3. 1 mol al2o3 = 6.02×10^23 particles al2o3 3.60 mol al2o3 = ?×10^? particles al2o3 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

Explanation:

Step1: Set up the proportion

We know that 1 mol of a substance contains $6.02\times 10^{23}$ particles (Avogadro's number). Let $x$ be the number of particles in 3.60 mol of $Al_2O_3$. The proportion is $\frac{1\ mol}{6.02\times 10^{23}\ particles}=\frac{3.60\ mol}{x}$.

Step2: Solve for $x$

Cross - multiply to get $x = 3.60\times6.02\times 10^{23}$ particles. Calculate $3.60\times6.02=21.672$. So $x = 21.672\times 10^{23}$ particles. In scientific notation, this is $2.17\times 10^{24}$ particles (rounded to two decimal places for the coefficient).

Answer:

Coefficient: 2.17, Exponent: 24