Question

determine what element is denoted by the following electron configuration: ar 4s²3d¹⁰4p³. n, mg, ba, as

Explanation:

Step1: Identify noble - gas core

The noble - gas core [Ar] represents 18 electrons. Argon (Ar) has an atomic number of 18.

Step2: Count remaining electrons

The remaining electron configuration is $4s^{2}3d^{10}4p^{3}$. The number of electrons in $4s^{2}$ is 2, in $3d^{10}$ is 10, and in $4p^{3}$ is 3. So the total number of remaining electrons is $2 + 10+3=15$.

Step3: Calculate total electrons

The total number of electrons of the element is the sum of electrons in the noble - gas core and the remaining electrons, which is $18 + 15=33$.

Step4: Determine the element

The element with an atomic number (number of electrons) of 33 is Arsenic (As).

Answer:

As