QUESTION IMAGE
Question
directions: how many grams are in the following elements and compounds?
- 3 moles of s
0.609 moles of fe
- 0.51 moles of so₂
0.142 moles of nacl
- 8 moles of mgf₂
0.428 moles of bacl₂
0.967 moles of c₃h₆o₃
- 0.97 moles of c₆h₁₂o₆
1.558 moles of ch₄
- 6 moles of lioh
- 2 moles of co₂
0.402 moles of al₂o₃
- 13 moles of he
0.384 moles of na₃po₄
- 0.48 moles of nh₄cl
0.001 moles of c₅h₁₁no₂
- 0.01 moles of ca(no₃)₂
- 0.42 moles of c₉h₈o₄
0.606 moles of (nh₄)₃po₄
2.415 moles of c₆h₁₀o₆
moles to grams, grams to moles worksheet
@ back-pocket science
The formula used for all problems is:
$$\text{Mass (g)} = \text{Moles} \times \text{Molar Mass (g/mol)}$$
Molar masses are calculated using atomic weights from the periodic table.
Step1: Calculate mass of S
Molar mass of S = $32.07\ \text{g/mol}$
$\text{Mass} = 3\ \text{mol} \times 32.07\ \text{g/mol} = 96.21\ \text{g}$
Step2: Calculate mass of SO₂
Molar mass of $\text{SO}_2 = 32.07 + 2(16.00) = 64.07\ \text{g/mol}$
$\text{Mass} = 0.51\ \text{mol} \times 64.07\ \text{g/mol} = 32.68\ \text{g}$
Step3: Calculate mass of MgF₂
Molar mass of $\text{MgF}_2 = 24.31 + 2(19.00) = 62.31\ \text{g/mol}$
$\text{Mass} = 8\ \text{mol} \times 62.31\ \text{g/mol} = 498.48\ \text{g}$
Step4: Calculate mass of C₆H₁₂O₆
Molar mass of $\text{C}_6\text{H}_{12}\text{O}_6 = 6(12.01) + 12(1.01) + 6(16.00) = 180.18\ \text{g/mol}$
$\text{Mass} = 0.97\ \text{mol} \times 180.18\ \text{g/mol} = 174.77\ \text{g}$
Step5: Calculate mass of Fe
Molar mass of Fe = $55.85\ \text{g/mol}$
$\text{Mass} = 0.609\ \text{mol} \times 55.85\ \text{g/mol} = 34.01\ \text{g}$
Step6: Calculate mass of NaCl
Molar mass of $\text{NaCl} = 22.99 + 35.45 = 58.44\ \text{g/mol}$
$\text{Mass} = 0.142\ \text{mol} \times 58.44\ \text{g/mol} = 8.29\ \text{g}$
Step7: Calculate mass of C₃H₆O₃
Molar mass of $\text{C}_3\text{H}_6\text{O}_3 = 3(12.01) + 6(1.01) + 3(16.00) = 90.09\ \text{g/mol}$
$\text{Mass} = 0.967\ \text{mol} \times 90.09\ \text{g/mol} = 87.12\ \text{g}$
Step8: Calculate mass of BaCl₂
Molar mass of $\text{BaCl}_2 = 137.33 + 2(35.45) = 208.23\ \text{g/mol}$
$\text{Mass} = 0.428\ \text{mol} \times 208.23\ \text{g/mol} = 89.12\ \text{g}$
Step9: Calculate mass of LiOH
Molar mass of $\text{LiOH} = 6.94 + 16.00 + 1.01 = 23.95\ \text{g/mol}$
$\text{Mass} = 6\ \text{mol} \times 23.95\ \text{g/mol} = 143.70\ \text{g}$
Step10: Calculate mass of CO₂
Molar mass of $\text{CO}_2 = 12.01 + 2(16.00) = 44.01\ \text{g/mol}$
$\text{Mass} = 2\ \text{mol} \times 44.01\ \text{g/mol} = 88.02\ \text{g}$
Step11: Calculate mass of Al₂O₃
Molar mass of $\text{Al}_2\text{O}_3 = 2(26.98) + 3(16.00) = 101.96\ \text{g/mol}$
$\text{Mass} = 0.402\ \text{mol} \times 101.96\ \text{g/mol} = 40.99\ \text{g}$
Step12: Calculate mass of CH₄
Molar mass of $\text{CH}_4 = 12.01 + 4(1.01) = 16.05\ \text{g/mol}$
$\text{Mass} = 1.558\ \text{mol} \times 16.05\ \text{g/mol} = 24.99\ \text{g}$
Step13: Calculate mass of NH₄Cl
Molar mass of $\text{NH}_4\text{Cl} = 14.01 + 4(1.01) + 35.45 = 53.50\ \text{g/mol}$
$\text{Mass} = 0.48\ \text{mol} \times 53.50\ \text{g/mol} = 25.68\ \text{g}$
Step14: Calculate mass of He
Molar mass of He = $4.00\ \text{g/mol}$
$\text{Mass} = 13\ \text{mol} \times 4.00\ \text{g/mol} = 52.00\ \text{g}$
Step15: Calculate mass of C₅H₁₁NO₂
Molar mass of $\text{C}_5\text{H}_{11}\text{NO}_2 = 5(12.01) + 11(1.01) + 14.01 + 2(16.00) = 117.16\ \text{g/mol}$
$\text{Mass} = 0.001\ \text{mol} \times 117.16\ \text{g/mol} = 0.12\ \text{g}$
Step16: Calculate mass of Na₃PO₄
Molar mass of $\text{Na}_3\text{PO}_4 = 3(22.99) + 30.97 + 4(16.00) = 163.94\ \text{g/mol}$
$\text{Mass} = 0.384\ \text{mol} \times 163.94\ \text{g/mol} = 62.95\ \text{g}$
Step17: Calculate mass of Ca(NO₃)₂
Molar mass of $\text{Ca(NO}_3\text{)}_2 = 40.08 + 2(14.01) + 6(16.00) = 164.10\ \text{g/mol}$
$\text{Mass} = 0.01\ \text{mol} \times 164.10\ \text{g/mol} = 1.64\ \text{g}$
Step18: Calculate mass of C₉H₈O₄
Molar mass of $\text{C}_9\text{H}_8\text{O}_4 = 9(12.01) + 8(1.01) + 4(16.00) = 180.17\ \text{g/mol}$
$\text{Mass} = 0.42\ \text{mol} \times 180.17\ \text{g/mol} = 75.67\ \text{g}…
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