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directions: how many grams are in the following elements and compounds?…

Question

directions: how many grams are in the following elements and compounds?

  1. 3 moles of s

0.609 moles of fe

  1. 0.51 moles of so₂

0.142 moles of nacl

  1. 8 moles of mgf₂

0.428 moles of bacl₂
0.967 moles of c₃h₆o₃

  1. 0.97 moles of c₆h₁₂o₆

1.558 moles of ch₄

  1. 6 moles of lioh
  2. 2 moles of co₂

0.402 moles of al₂o₃

  1. 13 moles of he

0.384 moles of na₃po₄

  1. 0.48 moles of nh₄cl

0.001 moles of c₅h₁₁no₂

  1. 0.01 moles of ca(no₃)₂
  2. 0.42 moles of c₉h₈o₄

0.606 moles of (nh₄)₃po₄
2.415 moles of c₆h₁₀o₆
moles to grams, grams to moles worksheet
@ back-pocket science

Explanation:

The formula used for all problems is:
$$\text{Mass (g)} = \text{Moles} \times \text{Molar Mass (g/mol)}$$
Molar masses are calculated using atomic weights from the periodic table.

Step1: Calculate mass of S

Molar mass of S = $32.07\ \text{g/mol}$
$\text{Mass} = 3\ \text{mol} \times 32.07\ \text{g/mol} = 96.21\ \text{g}$

Step2: Calculate mass of SO₂

Molar mass of $\text{SO}_2 = 32.07 + 2(16.00) = 64.07\ \text{g/mol}$
$\text{Mass} = 0.51\ \text{mol} \times 64.07\ \text{g/mol} = 32.68\ \text{g}$

Step3: Calculate mass of MgF₂

Molar mass of $\text{MgF}_2 = 24.31 + 2(19.00) = 62.31\ \text{g/mol}$
$\text{Mass} = 8\ \text{mol} \times 62.31\ \text{g/mol} = 498.48\ \text{g}$

Step4: Calculate mass of C₆H₁₂O₆

Molar mass of $\text{C}_6\text{H}_{12}\text{O}_6 = 6(12.01) + 12(1.01) + 6(16.00) = 180.18\ \text{g/mol}$
$\text{Mass} = 0.97\ \text{mol} \times 180.18\ \text{g/mol} = 174.77\ \text{g}$

Step5: Calculate mass of Fe

Molar mass of Fe = $55.85\ \text{g/mol}$
$\text{Mass} = 0.609\ \text{mol} \times 55.85\ \text{g/mol} = 34.01\ \text{g}$

Step6: Calculate mass of NaCl

Molar mass of $\text{NaCl} = 22.99 + 35.45 = 58.44\ \text{g/mol}$
$\text{Mass} = 0.142\ \text{mol} \times 58.44\ \text{g/mol} = 8.29\ \text{g}$

Step7: Calculate mass of C₃H₆O₃

Molar mass of $\text{C}_3\text{H}_6\text{O}_3 = 3(12.01) + 6(1.01) + 3(16.00) = 90.09\ \text{g/mol}$
$\text{Mass} = 0.967\ \text{mol} \times 90.09\ \text{g/mol} = 87.12\ \text{g}$

Step8: Calculate mass of BaCl₂

Molar mass of $\text{BaCl}_2 = 137.33 + 2(35.45) = 208.23\ \text{g/mol}$
$\text{Mass} = 0.428\ \text{mol} \times 208.23\ \text{g/mol} = 89.12\ \text{g}$

Step9: Calculate mass of LiOH

Molar mass of $\text{LiOH} = 6.94 + 16.00 + 1.01 = 23.95\ \text{g/mol}$
$\text{Mass} = 6\ \text{mol} \times 23.95\ \text{g/mol} = 143.70\ \text{g}$

Step10: Calculate mass of CO₂

Molar mass of $\text{CO}_2 = 12.01 + 2(16.00) = 44.01\ \text{g/mol}$
$\text{Mass} = 2\ \text{mol} \times 44.01\ \text{g/mol} = 88.02\ \text{g}$

Step11: Calculate mass of Al₂O₃

Molar mass of $\text{Al}_2\text{O}_3 = 2(26.98) + 3(16.00) = 101.96\ \text{g/mol}$
$\text{Mass} = 0.402\ \text{mol} \times 101.96\ \text{g/mol} = 40.99\ \text{g}$

Step12: Calculate mass of CH₄

Molar mass of $\text{CH}_4 = 12.01 + 4(1.01) = 16.05\ \text{g/mol}$
$\text{Mass} = 1.558\ \text{mol} \times 16.05\ \text{g/mol} = 24.99\ \text{g}$

Step13: Calculate mass of NH₄Cl

Molar mass of $\text{NH}_4\text{Cl} = 14.01 + 4(1.01) + 35.45 = 53.50\ \text{g/mol}$
$\text{Mass} = 0.48\ \text{mol} \times 53.50\ \text{g/mol} = 25.68\ \text{g}$

Step14: Calculate mass of He

Molar mass of He = $4.00\ \text{g/mol}$
$\text{Mass} = 13\ \text{mol} \times 4.00\ \text{g/mol} = 52.00\ \text{g}$

Step15: Calculate mass of C₅H₁₁NO₂

Molar mass of $\text{C}_5\text{H}_{11}\text{NO}_2 = 5(12.01) + 11(1.01) + 14.01 + 2(16.00) = 117.16\ \text{g/mol}$
$\text{Mass} = 0.001\ \text{mol} \times 117.16\ \text{g/mol} = 0.12\ \text{g}$

Step16: Calculate mass of Na₃PO₄

Molar mass of $\text{Na}_3\text{PO}_4 = 3(22.99) + 30.97 + 4(16.00) = 163.94\ \text{g/mol}$
$\text{Mass} = 0.384\ \text{mol} \times 163.94\ \text{g/mol} = 62.95\ \text{g}$

Step17: Calculate mass of Ca(NO₃)₂

Molar mass of $\text{Ca(NO}_3\text{)}_2 = 40.08 + 2(14.01) + 6(16.00) = 164.10\ \text{g/mol}$
$\text{Mass} = 0.01\ \text{mol} \times 164.10\ \text{g/mol} = 1.64\ \text{g}$

Step18: Calculate mass of C₉H₈O₄

Molar mass of $\text{C}_9\text{H}_8\text{O}_4 = 9(12.01) + 8(1.01) + 4(16.00) = 180.17\ \text{g/mol}$
$\text{Mass} = 0.42\ \text{mol} \times 180.17\ \text{g/mol} = 75.67\ \text{g}…

Answer:

  1. $96.21\ \text{g}$
  2. $32.68\ \text{g}$
  3. $498.48\ \text{g}$
  4. $174.77\ \text{g}$
  5. $34.01\ \text{g}$
  6. $8.29\ \text{g}$
  7. $87.12\ \text{g}$
  8. $89.12\ \text{g}$
  9. $143.70\ \text{g}$
  10. $88.02\ \text{g}$
  11. $40.99\ \text{g}$
  12. $24.99\ \text{g}$
  13. $25.68\ \text{g}$
  14. $52.00\ \text{g}$
  15. $0.12\ \text{g}$
  16. $62.95\ \text{g}$
  17. $1.64\ \text{g}$
  18. $75.67\ \text{g}$
  19. $90.35\ \text{g}$
  20. $430.26\ \text{g}$