a) draw the model for auto fuel economy. clearly label it, showing what the 68–95–99.7 rule predicts.
a.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 15.48, 18.59, 21.70, 24.81, 27.92, 31.03, 34.14
b.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 6.15, 12.37, 18.59, 24.81, 31.03, 37.2
c.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 6.15, 9.26, 15.48, 24.81, 34.14, 40.36, 43.47
d.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values - 12.51, - 0.07, 12.37, 24.81, 37.25, 49.69, 62
b) in what interval would you expect the central 95% of autos to be found?
using the 68–95–99.7 rule, the central 95% of autos can be expected to be found in the interval from 12.37 to 37.25 mpg. (type integers or decimals. do not round. use ascending order.)
c) about what percent of autos should get more than 31.03 mpg?
using the 68–95–99.7 rule, about 16 % of autos should get more than 31.03 mpg. (type an integer or a decimal. do not round.)
d) about what percent of autos should get between 31.03 and 37.25 mpg?
using the 68–95–99.7 rule, about % of autos should get between 31.03 and 37.25 mpg. (type an integer or a decimal. do not round.)

Question

a) draw the model for auto fuel economy. clearly label it, showing what the 68–95–99.7 rule predicts.
a.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 15.48, 18.59, 21.70, 24.81, 27.92, 31.03, 34.14
b.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 6.15, 12.37, 18.59, 24.81, 31.03, 37.2
c.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values 6.15, 9.26, 15.48, 24.81, 34.14, 40.36, 43.47
d.
image of normal - distribution curve with 68%, 95%, 99.7% labeled and values - 12.51, - 0.07, 12.37, 24.81, 37.25, 49.69, 62
b) in what interval would you expect the central 95% of autos to be found?
using the 68–95–99.7 rule, the central 95% of autos can be expected to be found in the interval from 12.37 to 37.25 mpg. (type integers or decimals. do not round. use ascending order.)
c) about what percent of autos should get more than 31.03 mpg?
using the 68–95–99.7 rule, about 16 % of autos should get more than 31.03 mpg. (type an integer or a decimal. do not round.)
d) about what percent of autos should get between 31.03 and 37.25 mpg?
using the 68–95–99.7 rule, about  % of autos should get between 31.03 and 37.25 mpg. (type an integer or a decimal. do not round.)

Accepted Answer

# Explanation:
## Step1: Recall 68 - 95 - 99.7 Rule
The 68 - 95 - 99.7 Rule for a normal distribution states that about 68% of the data is within 1 standard - deviation of the mean, about 95% is within 2 standard - deviations of the mean, and about 99.7% is within 3 standard - deviations of the mean.
## Step2: Analyze part d
We know that the central 95% of the data is within 2 standard - deviations of the mean. The central 68% is within 1 standard - deviation of the mean. The interval from 31.03 to 37.25 is part of the outer part of the 95% interval but within the 2 - standard - deviation range.
The 95% interval is symmetric about the mean. The 68% interval is also symmetric about the mean. The percentage of data above 31.03 is (100 - 68)/2=16% (from part c). The percentage of data above 37.25 is (100 - 95)/2 = 2.5%.
To find the percentage of data between 31.03 and 37.25, we subtract the percentage above 37.25 from the percentage above 31.03. So, 16−2.5 = 13.5.

# Answer:
13.5

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QUESTION IMAGE

Question

Explanation:

Step1: Recall 68 - 95 - 99.7 Rule

Step2: Analyze part d

Answer: