Question

during final exam weeks, many college students exercise to fuel their study sessions. data from a recent survey are shown in the venn diagram. let m be the event that the student exercises in the morning and let a be the event that the student exercises in the afternoon. what is the probability that a randomly - chosen college student exercises in the morning or afternoon? exercise habits m a 0.25 0.37 0.14 0.24 0.37 0.39 0.76 0.62

Explanation:

Step1: Recall probability formula for union

The formula for $P(M\cup A)$ is $P(M)+P(A)-P(M\cap A)$.

Step2: Calculate $P(M)$

$P(M)=0.25 + 0.37=0.62$.

Step3: Calculate $P(A)$

$P(A)=0.37+0.14 = 0.51$.

Step4: Identify $P(M\cap A)$

$P(M\cap A)=0.37$.

Step5: Substitute values

$P(M\cup A)=0.62 + 0.51- 0.37$.
$P(M\cup A)=0.76$.

Answer:

$0.76$