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Question
electromagnetic spectrum
wavelength increasing
10 1 10^(-2) 10^(-4) 10^(-6) 10^(-8) 10^(-10) 10^(-12) 10^(-14) meters
wavelength ((lambda))
radio waves tv waves microwaves infrared radiation ultraviolet radiation x - rays y - rays cosmic rays
frequency ((
u)) 3x10^(8) 3x10^(10) 3x10^(12) 3x10^(14) 3x10^(16) 3x10^(18) 3x10^(20) 3x10^(22) 1/seconds
frequency increasing
which of these correctly shows types of radiation increasing in energy?
x - rays, ultraviolet radiation, microwaves, radio waves
microwaves, radio waves, x - rays, ultraviolet radiation
radio waves, microwaves, x - rays, ultraviolet radiation
Step1: Recall energy - frequency - wavelength relation
The energy of a photon is given by $E = h
u$, where $h$ is Planck's constant and $
u$ is the frequency. Also, $c=\lambda
u$ (where $c$ is the speed of light), so $
u=\frac{c}{\lambda}$. Higher frequency or lower wavelength means higher energy.
Step2: Analyze the electromagnetic - spectrum
From the electromagnetic - spectrum, radio waves have the longest wavelength and lowest frequency, followed by microwaves, then infrared, then visible light, then ultraviolet, then X - rays, and finally gamma - rays and cosmic rays with the shortest wavelength and highest frequency.
Step3: Evaluate the options
The correct order of increasing energy (i.e., increasing frequency or decreasing wavelength) is radio waves, microwaves, ultraviolet radiation, X - rays. But among the given options, the correct order of increasing energy is radio waves, microwaves, ultraviolet radiation, X - rays.
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None of the given options are correct. The correct order should be radio waves, microwaves, ultraviolet radiation, X - rays.