Question

electron configurations worksheet
write the complete ground state electron configurations for the following:

1. lithium
2. oxygen
3. calcium
4. titanium
5. rubidium
6. lead
7. erbium

write the abbreviated ground state electron configurations for the following:

1. helium
2. nitrogen
3. chlorine
4. iron
5. zinc
6. barium
7. polonium

Explanation:

Step1: Recall electron - filling rules

Electrons fill orbitals in order of increasing energy (Aufbau principle), with a maximum of 2 electrons in an s - orbital, 6 in a p - orbital, 10 in a d - orbital, and 14 in an f - orbital. We use the periodic table to determine the number of electrons and their configuration.

Step2: Determine lithium's configuration

Lithium (Li) has 3 electrons. The electron configuration is $1s^{2}2s^{1}$.

Step3: Determine oxygen's configuration

Oxygen (O) has 8 electrons. The electron configuration is $1s^{2}2s^{2}2p^{4}$.

Step4: Determine calcium's configuration

Calcium (Ca) has 20 electrons. The electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}$.

Step5: Determine titanium's configuration

Titanium (Ti) has 22 electrons. The electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{2}$.

Step6: Determine rubidium's configuration

Rubidium (Rb) has 37 electrons. The electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}$.

Step7: Determine lead's configuration

Lead (Pb) has 82 electrons. The electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{2}$.

Step8: Determine erbium's configuration

Erbium (Er) has 68 electrons. The electron configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{12}$.

Step9: Determine helium's abbreviated configuration

Helium (He) has 2 electrons. The abbreviated configuration is $[He]$.

Step10: Determine nitrogen's abbreviated configuration

Nitrogen (N) has 7 electrons. The abbreviated configuration is $[He]2s^{2}2p^{3}$.

Step11: Determine chlorine's abbreviated configuration

Chlorine (Cl) has 17 electrons. The abbreviated configuration is $[Ne]3s^{2}3p^{5}$.

Step12: Determine iron's abbreviated configuration

Iron (Fe) has 26 electrons. The abbreviated configuration is $[Ar]4s^{2}3d^{6}$.

Step13: Determine zinc's abbreviated configuration

Zinc (Zn) has 30 electrons. The abbreviated configuration is $[Ar]4s^{2}3d^{10}$.

Step14: Determine barium's abbreviated configuration

Barium (Ba) has 56 electrons. The abbreviated configuration is $[Xe]6s^{2}$.

Step15: Determine polonium's abbreviated configuration

Polonium (Po) has 84 electrons. The abbreviated configuration is $[Xe]6s^{2}4f^{14}5d^{10}6p^{4}$.

Answer:

1. $1s^{2}2s^{1}$
2. $1s^{2}2s^{2}2p^{4}$
3. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}$
4. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{2}$
5. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}$
6. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{2}$
7. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}6s^{2}4f^{12}$
8. $[He]$
9. $[He]2s^{2}2p^{3}$
10. $[Ne]3s^{2}3p^{5}$
11. $[Ar]4s^{2}3d^{6}$
12. $[Ar]4s^{2}3d^{10}$
13. $[Xe]6s^{2}$
14. $[Xe]6s^{2}4f^{14}5d^{10}6p^{4}$