Question

enrollments for selected independent religiously controlled 4-year colleges listed below are the enrollments for selected independent religiously controlled 4-year colleges that offer bachelor’s degrees only for a recent year. construct a grouped frequency distribution with six classes and find the mean and modal class.
1530 2819 2595 2131 2750 1445 2970 2785
2528 2922 1999 1170 2391 3315 2046 2643
3275 1037 3049 3465 3182 1780 1610 2813
2016 2176 2225 3385 2688 3067 3152 3490
2379
part 1 of 6
(a) what is the class width for a frequency distribution with 6 classes?
the class width is .

Explanation:

1. Correct. So 2453 divided by 6 is approximately 408.83, so we round up to 409. But maybe the problem has a different approach. Wait, maybe the data is different. Wait, let's check the original problem again. The problem says "enrollments for selected independent religiously controlled 4-year colleges". Maybe the data is:

Wait, let's list all the numbers:

1530, 2819, 2595, 2131, 2750, 1445, 2970, 2785,

2528, 2922, 1999, 1170, 2391, 3315, 2046, 2643,

3275, 1037, 3049, 3465, 3182, 1780, 1610, 2813,

2016, 2176, 2225, 3385, 2688, 3067, 3152, 3490,

2379.

Yes, that's 33 numbers. So min 1037, max 3490. So range 2453. Number of classes 6. So class width is $\lceil\frac{2453}{6}
ceil = 409$. But maybe the problem expects 400? Wait, no, let's check with 400. 6 classes with width 400: starting at 1000, then 1400, 1800, 2200, 2600, 3000, 3400. But 1037 is in 1000-1399, 1170, 1445 (1400-1799), 1530, 1610, 1780, 1999 (1800-2199), 2016, 2046, 2131, 2176, 2225 (2200-2599), 2379, 2391, 2528, 2595, 2643, 2688, 2750, 2785, 2813, 2819, 2922, 2970 (2600-2999), 3049, 3067, 3152, 3182, 3275, 3315, 3385, 3465, 3490 (3000-3399? No, 3000-3399, then 3400-3799). Wait, 3465 and 3490 would be in 3400-3799. So 6 classes: 1000-1399, 1400-1799, 1800-2199, 2200-2599, 2600-2999, 3000-3399, 3400-3799? No, that's 7 classes. So maybe my initial calculation is wrong. Wait, maybe the min is 1037, max is 3490. So 3490 - 1037 = 2453. 2453 /6 = 408.83, so we take 409. So the class width is 409. But maybe the problem expects 400? Wait, no, let's check the data again. Wait, maybe I made a mistake in the max. Let's check the numbers: 3490 is the last number. Yes. So 3490 is the max. So range is 2453. So class width is 409.

Wait, but maybe the problem has a different data set. Wait, maybe the original data is different. Wait, let's check the problem statement again. The problem says "Enrollments for Selected Independent Religiously Controlled 4-Year Colleges Listed below are the enrollments...". Maybe the data is:

1530, 2819, 2595, 2131, 2750, 1445, 2970, 2785,

2528, 2922, 1999, 1170, 2391, 3315, 2046, 2643,

3275, 1037, 3049, 3465, 3182, 1780, 1610, 2813,

2016, 2176, 2225, 3385, 2688, 3067, 3152, 3490,

2379.

Yes, that's correct. So min 1037, max 3490. So range 2453. Number of classes 6. So class width is $\lceil\frac{2453}{6}
ceil = 409$.

Answer:

409