Question

1. the equation below shows a chemical reaction. according to the law of conservation of mass, what will be the mass (in grams) of carbon dioxide (co₂) formed in the product? 2c₂h₆ + 7o₂ → 4co₂ + 6h₂o enter your answer below.

Explanation:

Step1: Recall the law of conservation of mass

The total mass of reactants equals the total mass of products. First, find the total mass of reactants.
The mass of reactants is the sum of the mass of $C_2H_6$ and $O_2$. But we are not given the masses of reactants separately in a way to calculate from reactant - side. So, we calculate from the product - side.

Step2: Calculate the mass of products

The products are $CO_2$ and $H_2O$. Let the mass of $CO_2$ be $x$ grams and the mass of $H_2O$ be $4.49$ grams.
We know that the sum of the mass of $CO_2$ and $H_2O$ should satisfy the law of conservation of mass.
The sum of the masses given for parts of the products and reactants can be used. Let's assume the total mass of reactants is the sum of the two given masses of reactant - like quantities: $2.5+9.31 = 11.81$ grams.
By the law of conservation of mass, the total mass of products is also $11.81$ grams.
Since the mass of $H_2O$ is $4.49$ grams, we can find the mass of $CO_2$.
We use the equation $x+4.49=11.81$.

Step3: Solve for the mass of $CO_2$

Subtract $4.49$ from both sides of the equation $x + 4.49=11.81$.
$x=11.81 - 4.49$
$x = 7.32$ grams

Answer:

$7.32$ grams