Question

example 6: the spinner shown is divided into congruent sections. if the spinner is spun one time, what is the probability of the arrow not landing on a section labeled even number? a $\frac{3}{5}$ b $\frac{1}{5}$ c $\frac{4}{5}$ d $\frac{2}{5}$

Explanation:

Step1: Count total sections

Total sections = 10

Step2: Count even-numbered sections

Even numbers: 2,4,2,4,2,4 → Total = 6

Step3: Calculate probability of even number

Probability (even) = $\frac{\text{Even sections}}{\text{Total sections}} = \frac{6}{10} = \frac{3}{5}$

Step4: Find probability of NOT even

Probability (not even) = $1 - \frac{3}{5} = \frac{2}{5}$

Answer:

D. $\frac{2}{5}$