Question

exit ticket (limiting and excess reactants, stoichiometry and % yield) - k 2 of 5 use the reaction below to answer the question. be sure to include units and substance in your response. fecl₃ + 3naoh → fe(oh)₃ + 3nacl how many grams of naoh are needed to react in order to produce 4.322 moles of nacl? (record your answer in \3\ significant figures.)

Explanation:

Step1: Find mole ratio of NaOH:NaCl

From reaction: $\frac{n(\text{NaOH})}{n(\text{NaCl})} = \frac{3}{3} = 1$

Step2: Calculate moles of NaOH

$n(\text{NaOH}) = n(\text{NaCl}) = 4.32\ \text{mol}$

Step3: Calculate molar mass of NaOH

$M(\text{NaOH}) = 23 + 16 + 1 = 40\ \text{g/mol}$

Step4: Compute mass of NaOH

$m(\text{NaOH}) = n \times M = 4.32\ \text{mol} \times 40\ \text{g/mol}$

Answer:

$173\ \text{grams}$