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in an experiment, the probability that event a occurs is $\frac{5}{8}$,…

Question

in an experiment, the probability that event a occurs is $\frac{5}{8}$, the probability that event b occurs is $\frac{3}{7}$, and the probability that events a and b both occur is $\frac{2}{9}$. what is the probability that a occurs given that b occurs? simplify any fractions.

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$.

Step2: Identify given probabilities

We are given that $P(A)=\frac{5}{8}$, $P(B)=\frac{3}{7}$, and $P(A\cap B)=\frac{2}{9}$.

Step3: Substitute values into formula

Substitute $P(A\cap B)=\frac{2}{9}$ and $P(B)=\frac{3}{7}$ into the formula $P(A|B)=\frac{P(A\cap B)}{P(B)}$, we get $P(A|B)=\frac{\frac{2}{9}}{\frac{3}{7}}$.

Step4: Simplify the fraction

To divide by a fraction, we multiply by its reciprocal. So $P(A|B)=\frac{2}{9}\times\frac{7}{3}=\frac{14}{27}$.

Answer:

$\frac{14}{27}$