Question

9 fill in the blank 1.25 points if someone took an lsat test and received a 143, what percentage of scores will be greater than this? step 4. report the answer. please interpret the answer by filling in the blank. the percentage of lsat scores that are choose your answer... than choose your answer..., in a normal distribution with a μ = choose your answer... (σ = choose your answer...), is choose your answer... %.

Explanation:

Step1: Assume LSAT scores are normally - distributed with mean $\mu = 150$ and standard deviation $\sigma = 10$ (common values).

First, calculate the z - score using the formula $z=\frac{x-\mu}{\sigma}$, where $x = 143$, $\mu = 150$, and $\sigma = 10$. So, $z=\frac{143 - 150}{10}=\frac{-7}{10}=- 0.7$.

Step2: Use the standard normal distribution table.

The standard normal distribution table gives the cumulative probability $P(Z\lt z)$. Looking up $z=-0.7$ in the table, we find $P(Z\lt - 0.7)=0.2420$.

Step3: Calculate the probability of scores greater than 143.

We want $P(Z\gt - 0.7)$. Since the total area under the normal - distribution curve is 1, $P(Z\gt - 0.7)=1 - P(Z\lt - 0.7)$. So, $P(Z\gt - 0.7)=1 - 0.2420 = 0.7580$.

Answer:

The percentage of LSAT scores that are greater than 143, in a normal distribution with a $\mu = 150$ ($\sigma = 10$), is 75.8%.