Question

fill in the blank question
a cars tires push on the ground with $-150$ n of force forward. if the tires do not slip, then the ground pushes on the tires with $\boldsymbol{\square}$ n of force forward. if there are no other horizontal forces on the 1500 kg car, it will experience an acceleration of $\boldsymbol{\square}$ m/s² forward.

Explanation:

Step1: Apply Newton's Third Law

Newton's third law states that for every action, there is an equal and opposite reaction. The tires exert a force of $-150\ \text{N}$ forward on the ground, so the ground exerts an equal and opposite force on the tires.
$\text{Force from ground} = 150\ \text{N}$

Step2: Apply Newton's Second Law

Use $F=ma$ to find acceleration, rearranged to $a=\frac{F}{m}$. The mass $m=1500\ \text{kg}$ and net force $F=150\ \text{N}$.
$a=\frac{150}{1500}=0.1\ \text{m/s}^2$

Answer:

150, 0.1